WebIf 2a + 3b = 7 and ab = 2, find 4a 2 + 9b 2. Expansions ICSE. 3 Likes. Answer. We know that, a 2 + b 2 = (a + b) 2 - 2ab. ∴ 4a 2 + 9b 2 = (2a) 2 + (3b) 2 = (2a + 3b) 2 - 12ab. Substituting values we get, ⇒ 4a 2 + 9b 2 = (7) 2 - 12 × 2. ⇒ 4a 2 + 9b 2 = 49 - 24. ⇒ 4a 2 + 9b 2 = 25. Hence, 4a 2 + 9b 2 = 25. Answered By. 3 Likes. Related ... Web2a+5-(a-7)=48 One solution was found : a = 36 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...
Answered: 2 9. If a * b = 2a – 3b + 4ab, find the… bartleby
Web30 mrt. 2024 · Transcript. Example 9 Find the value of the following expressions for a = 3, b = 2. (i) a + b a + b Putting a = 3 , b = 2 = 3 + 2 = 5 Example 9 Find the value of the following expressions for a = 3, b = 2. (ii) 7a – 4b 7a – 4b Putting a = 3, b = 2 = 7 (3) − 4 (2) = 21 − 8 = 13 Example 9 Find the value of the following expressions for a ... Web7 mrt. 2024 · E. 34. a + b − 2c = 12. 3a + 3b + c = 22. 3 variables 2 equations obviously mean that we will have to modify equations and cancel the undesired variables. 3 (a + b − 2c) = 3 (12) becomes 3a+3b-6c=36. So now we have. 3a+3b-6c=36. 3a + 3b + c = 22. Subtract 2 from 1. hauntings in britain
[Solved] If A = diag [3, - 5, 7] and B = diag [- 1, 2, 4] then find t
Web28 mrt. 2024 · Its area is (a) 225 cm 2 (b) 225 3 cm 2 (c) 225 2 cm 2 (d) 450 cm 2 14. Each of the two equal sides of an isosceles right triangle is 10 cm long. Its area is (a) 5 10 cm 2 (b) 50 cm (c) 10 3 cm 2 (d) 75 cm 15. The area of the curved surface of a cone of radius 2 r and slant height 2 1 , is (a) π r (b) 2 π r (c) 2 1 π Il (d) π (r + I) r 16. WebIn algebra, we use letters to represent particular numbers which is a bit like using the code above.. Substituting numbers for letters For this example, we need to give the letters a, b and c some values. We will let a have the value 4, b have the value 7, and c have the value 3. Normally we would write: a = 4, b = 7, c = 3. If we see an expression which … WebQ. If a and b are the non-zero distinct roots of x2+ax+b=0, then the least value of quadratic polynomial x2+ax+b is. If α and β are zeroes of the polynomial x 2 - a (x + 1) - b such that (α + 1) ( β + 1) = 0, find the value of b. If ' a ' and ' b ' are the non-zero distinct zeros of x2+ax+b, then the least value of quadratic polynomial x2 ... border cross jack russell puppies for sale