Web1 I've got this: $$\sum_ {k=1}^ {n}\frac {1} {2^ {2k}}$$Wolfram Alpha already simplified it for me as $\dfrac {2^ {2n}-1} {3\cdot2^ {2n}}$, but he hasn't told me why. summation Share Cite Follow asked Dec 2, 2013 at 19:56 k5f 641 5 17 1 Would it help to note $\frac {1} {2^ {2k}} = \left (\frac {1} {4}\right)^k$? – Jonathan Y. Dec 2, 2013 at 19:59

Step-by-Step Math Problem Solver

WebA worked example of simplifying an expression that is a sum of several radicals. In this example, we simplify √(2x²)+4√8+3√(2x²)+√8. Created by Sal Khan and Monterey Institute … WebThe bottom numbers (the denominators) are already the same. Go straight to step 2. Step 2. Add the top numbers and put the answer over the same denominator: 1 4 + 1 4 = 1 + 1 4 = 2 4. Step 3. Simplify the fraction: 2 4 = 1 2. In picture form it looks like this: crystal and crochet floralia

Summation notation (also called sigma notation) (article)

WebJust consider the set { 1, 1, 2, 2, 3, 3, … } then the sum of first 2 n terms is. S 2 n = 2 ∑ i = 1 n i = 2 ( 1 + 2 + ⋯ + n) = n ( n + 1) This can be seen by summing 1 + 2 + ⋯ + n with n + ( n − … WebApr 9, 2008 · You need to multiply each term in the 2nd sum by each one in the first sum, which gives you 9 products. Then group terms to get the simplified final expression. Carrying out the multiplication, I get this: !AA + !AB + !AC + BA + BB + BC + CA + CB + CC WebSimple Sum (2008) The Way the World Looks (2009) Simple Sum is the first studio album by Australian singer-songwriter, Wes Carr.Carr recorded the album in 2007 at Sydney's … crystal and company insurance